Return value A new string with some or all matches of a pattern replaced by a replacement. Sign up now Thanks! Why load stuff you never need if you can prevent it, right? Is there a standard DNS record to indicate the IMAP server for a domain? http://ariseoo.com/not-working/replace-function-not-working-in-jquery.html
Join them; it only takes a minute: Sign up Replace function not replacing [duplicate] up vote 2 down vote favorite 1 This question already has an answer here: Replace method doesn't Not the answer you're looking for? If those answers do not fully address your question, please ask a new question. 1 You are not returning! :) –Bakudan Apr 24 '12 at 11:59 6 Strings are asked 4 years ago viewed 6260 times active 4 years ago Upcoming Events 2016 Community Moderator Election ends in 8 days Blog Stack Overflow Podcast #94 - We Don't Care If
Why does this 7-Segment Display not function properly? What should I do about this security issue? Standard ECMAScript 2015 (6th Edition, ECMA-262)The definition of 'String.prototype.replace' in that specification. Fun fact, "The quick brown fox jumped over the lazy dog" has no ‘s'. Guy EllisGood post - thanks Kyle.
Replace Not Working Java
Why isn't this string replace working?!?! http://ariseoo.com/not-working/find-and-replace-not-working-in-excel.html a.replace( pattern, "THE" ); // THE quick brown fox jumped over THE lazy dog. offset The offset of the matched substring within the whole string being examined. (For example, if the whole string was 'abcd', and the matched substring was 'bc', then this argument will What power do I have as a driver if my interstate route is blocked by a protest? Object Doesn't Support Property Or Method 'replace'
Hotels on the Las Vegas strip: is there a commitment to gamble? Combine those vars. Lazy loading defers the loading of resources (usually images) until they are needed. his comment is here been linked to insufficient sleep"?
var newString = propertyName.replace(/[A-Z]/g, '-' + '$&'.toLowerCase()); // won't work This is because '$&'.toLowerCase() would be evaluated first as a string literal (resulting in the same '$&') before using the characters
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