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Read File From Relative Path In Java Example


posted 3 years ago What did you intend that relative path to be relative to? For example, the next snippet tries to retrieve the mojo logger during construction time but the mojo logger is an injected component and as such has not been properly initialized yet: Try Compiling and Running the Examples: FAQs. Properties properties = new Properties(); properties.load(getClass().getResourceAsStream("ListStopWords.txt")); Note: when you're trying to access it from inside static context, then use FileLoader.class instead of getClass() in above examples. this contact form

Due to the lookup strategy performed by ResourceBundle.getBundle(), one must always provide a dedicated resource bundle for this default language, too. Score a hand of Hearts Storing passwords in access-restricted Google spreadsheets? In other words, components required by a mojo will be provided by means of dependency injection, more precisely field injection. folder and build\classes\...

Read File From Relative Path In Java Example

This is best noticed when the output directory for the site is configured directly in the Maven Site Plugin such that it deviates from the expression ${project.reporting.outputDirectory} that the plugins use A file encoding (aka charset) is used to convert between bytes and characters. Chess : The Lone King Munchkin: Charity: Giving cards to someone who has 5 already How would you say "to scold" in a less formal way?

to delete temporary files as shown in the example below: public MyMojo extends AbstractMojo { public void execute() { File tempFile = File.createTempFile( "temp", null ); /* * FIXME: This assumes The implementation of AbstractMavenReport.getOutputDirectory() is only intended as a fallback in case the mojo is not run as part of the site generation. How to stop a Linux process for later execution swapping-out its memory How to find the maximal number of elements of an array? Read File From Path Java Creating Resource Bundle Families Especially reporting plugins employ resource bundles to support internationalization.

All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton How To Java Filereader Absolute Path share|improve this answer edited May 18 '10 at 20:10 answered May 18 '10 at 20:03 erickson 182k33271390 add a comment| up vote 3 down vote It must be a FileNotFoundException causing It is a purely syntactic operation. more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation

means the parent folder of the currently running context. Java File Relative Path Example Permalink Posted 9-Sep-11 2:14am TorstenH.34.9K v2 Comments painjofshem 9-Sep-11 7:36am I have to give arguments if I want to run my application, that means, I have to give getName(0) home home Returns the path element corresponding to the specified index. Class myClass = getClass(); works in any instance method.

  • Solution 1 Accept Solution Reject Solution Other files like pictures, icons, print templates? - add a folder "resource" to your project aside of the folder "src" - underneath build up a decent structure
  • Absolute Path issue in frame src attribute (How) can I use relative path in "Find in Files" dialog?
  • posted 3 years ago There is no way to do that.
  • If you need to convert the path to a string that can be opened from a browser, you can use toUri.
  • A root element or a file name might be included, but neither are required.
  • This method is described in the next section, Converting a Path.
  • painjofshem 7-Nov-11 3:48am I know, thx Rate this: Please Sign up or sign in to vote.
  • Nothing wrong so far.
  • java eclipse share|improve this question asked May 18 '10 at 19:54 Richard Knop 23.8k95284462 Can you please mark line number 24 in your source? –tangens May 18 '10 at
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Java Filereader Absolute Path

getFileName foo foo Returns the file name or the last element of the sequence of name elements. In my instance I'm trying to open a file which is located in a test package. –Robin Newhouse Oct 9 '14 at 1:19 | show 1 more comment up vote 20 Read File From Relative Path In Java Example And what was the current working directory when you ran that code? How To Give The Relative Path Of File In Java Did a short edit to my code & it worked.

To prevent conflicts with other code running in the same JVM, Maven plugins should instead query the execution properties. weblink You can also put Path objects into a Collection. To navigate from joe to sally, you would expect to first navigate one level up to the parent node and then down to sally: // Result is ../sally Path p1_to_p2 = So the question is how do you know the path where the java is currently looking? How To Read A File From A Specified Path In Java

The above code does not handle this case. The later will print the working directory. the code defect is not immediately noticeable by a NullPointerException. navigate here But that's pure logic - you can't use relative paths when you're not able to address your files correctly.

And indeed, class loaders from Sun JREs up to Java 1.4 will deliver malformed URLs when queried for a resource. Java Read File Absolute Path If you construct the File object using a URI rather than a String, whitespaces will be handled correctly: URL url = getClass().getResource("ListStopWords.txt"); File file = new File(url.toURI()); share|improve this answer answered Both of the preceding examples normalize to /home/joe/foo.

By default the absolut path is listed under "User Entries" in [icon] 'your.path' (default classpath) share|improve this answer answered Nov 17 '14 at 15:45 theSaan 11 add a comment| up vote

Campbell Ritchie Sheriff Posts: 51092 85 posted 3 years ago And welcome to the Ranch Remember that .. Rate this: Please Sign up or sign in to vote. Path names are platform-specific, so you've just destroyed Java's platform independence. Filereader From Path Javascript The important point to keep in mind is that this field injection happens after the mojo's constructor has finished.

For example: Path path = ...; Path otherPath = ...; Path beginning = Paths.get("/home"); Path ending = Paths.get("foo"); if (path.equals(otherPath)) { // equality logic here } else if (path.startsWith(beginning)) { // The toRealPath method returns the real path of an existing file. If the JVM is then executing a bunch of other Maven builds, many such cleanup tasks can sum up, eating up resources of the JVM. http://ariseoo.com/relative-path/asp-net-relative-path.html Unfortunately, the class java.io.File does not resolve relative paths against the project's base directory.

share|improve this answer edited Oct 2 '10 at 4:14 answered Oct 2 '10 at 3:56 BalusC 690k21425062720 Was FileLoader removed from java? As such, usage of the default encoding threatens the dream of a reproducible build. The meaning of 'already' in the sentence 'Let's go already!' Why does my Probability function not work Hotels on the Las Vegas strip: is there a commitment to gamble? FileReader r = new FileReader(path); Putting this all together, and leaving out the unnecessary variables, we have: FileReader r = new FileReader(RelativeFile.class.getClassLoader() .getResource("dummy.txt").getPath() .replaceAll("%20", " ")); See?

The following code snippet iterates over a path, printing each name element: Path path = ...; for (Path name: path) { System.out.println(name); } The Path class also implements the Comparable interface. and your file is present in the folder MyProject simply use File resourceFile = new File("../myFile.txt"); Hope this helps share|improve this answer answered Nov 11 at 16:09 Samrat 5317 add a For this reason, plugin developers should avoid usage of shutdown hooks and rather use try/finally blocks to perform cleanup as soon as the resources are no longer needed.